what would be the slope intercept form of the line that is perpendicular to 7x+3y=18 and contains the point (6,8)

Question

anonymous · Answer

slope intercept form is y = mx + b

7x + 3y = 18 => 3y = -7x + 18 
                  7
=> y = - --- x + 6
                  3

If a line is perpendicular to this, then its slope is negative reciprocal of the first line
so the slope of the perpendicular line = 3/7

now m = 3/7, x= 6 and y =8
so
          3
8 = ---- (6) + b
          7
8 = 18/7 + b

8 - 18/7 = b

38/7 = b

so the equation for perpendicular line will be
         3             38
y = ---- x + -----
         7               7

7y = 3x + 38
or
3x - 7y = -38

anonymous · Answer

slope intercept form would be

         3             38
y = ---- x + -----
         7               7