Question

solve...2^(x+3)=7?

Answer 1

\[\large x = \log_2 7 - 3\]

Answer 2

2^(x+3)=7

ln(2^(x+3))=ln(7)

xln(2)+3ln(2)=ln(7)

xln(2)=-3ln(2)+ln(7)

x=-(3ln(2))/(ln(2))+ln(7)/ln(2)

x=(-3ln(2)+ln(7))/ln(2)
x=-0.1926