Question

Calculate the turning point(s) of the function y = (x^2-2x)/x^1/2 . Use this to sketch the graph of this function.

Answer 1

The equation is \[y=(x^2 - 2x)\div \sqrt{x}\]
as I know, at first I have to find the derivative of this function, so I get \[((3x-2)\sqrt{x)} 2\] but i'm not sure if I did it right (I used the Quatient rule). Please help