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logx+log(x+3)=1 what does x=
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\[\log_{10}x+\log_{10}(x+3)=1 \]
log x ( x+3) = 1 -> x^2 + 3x = 10 -> x^2 + 3x - 10 = 0 -> ( x + 5) ( x -2) = 0 => x = 2 ( discard x = -5 < 0)
um were did you get the 10 from
because base 10 -> 10^1 = 10
I'm in hurry!
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so whatever the base is you raise that number to whatever it is in the =sign then if that makes sence
Yep, it's from the formula!
Log base a of x = y => x = a^y
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