Question

find f'(a) of radical (1-2x) how do i solve this?

Answer 1

so \[y = \sqrt{1 -2x}\]

or \[y = (1 -2x)^{1/2}\]

use the chain rule

let u = 1-2x du/dx = -2

so

\[y = u^{1/2}\]

dy/dx = dy/du x du/dx


\[y' = 1/2(1 -2x)^{-1/2} \times -2\]
\[y' = -1/(\sqrt{1-2x})\]