Question

The sum of two numbers is 46. The sum of the smaller and 3 times the larger is 104. Find the numbers.

Answer 1

let x and y be the smaller and larger no respectively
x+y = 46 => x=46-y (1)
x+3y = 104 (2)
Put (1) into (2)
y = 29, x=46-29=17

Answer 2

let smaller no = x
larger no = y

x + y = 46 -------- i
x + 3y = 104 ------- ii

subtract ii from i
-2y = - 58
y = -58/-2
y = 29

so larger no is 29
smaller no is 46 - 29 = 17

Answer 3

Thank you!