Question

Is anyone good at pre-calculous?

Answer 1

lemme try

Answer 2

pre-calculus *

Answer 3

ya sorry mispelled it

Answer 4

what's your question?

Answer 5

Idk just wondering if anyone is good at the 2nd half of the year in pre cal?

Answer 6

I dont know how to respond to that.

Answer 7

\[\sin *\tan =? \]

Answer 8

\[\frac{\sin ^{2}x}{cosx}\]

Answer 9

sin (t)* tan (t)= -1/2 (cos(2t)-1) sec(t)
or, if you prefer:
\[-\frac{(e^{-it}-e^{it})^2}{2(e^{-it}+e^{it})}\]

Answer 10

or sin^x/cosx
there are a number of answer to this question.

Answer 11

sin^2 x/cosx *