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what would the slope of this be: Find an equation for the tangent line to the graph of f(x) = (4−x)^3 at the point (2, 8).
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You know how to take the derivative of the function?
i got derivative = 192x^2 ?
hmm, that doesn't sound correct... f(x) = (4-x)^3 you could use chain rule here
i didn't think so. lol
-3x^2+24x-48... there we go.
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would the answer => y=32-12x ??
Yeah, that is correct. :)
|dw:1330973000925:dw|
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