Question

Solve for x. √2x+3= √6x-1
all numbers are under the rad sign

Answer 1

\[\sqrt{2x+3}=\sqrt{6x-1}\]
\[\sqrt{2x+3}^2=\sqrt{6x-1}^2 \implies \cancel{\sqrt{}}(2x+3)\cancel{^2}=\cancel{\sqrt{}}(6x-1)\cancel{^2}\]
\[2x+3=6x-1\]
\[-4x=-4\]
\[x=1\]

Answer 2

thankyouu