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Mathematics 9 Online
OpenStudy (anonymous):

A ball at the end of a 2-m rope swings in a vertical arc. Its speed at the bottom of the swing is 8 m/s. What will be its speed when it is at a position where the rope is horizontal?

OpenStudy (anonymous):

v= square root of (m*length*(1-costheta) ) and theta is 90 right?? :( where am i going wrong?

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