Question

Pic help.
In △JKL, solve for x.

A: 30.29
B: 38.16
C: 66.73
D: 74.89

Answer 1

I'm a bit rusty on my trig, but the solution should be cos(angle)=adjacent/hypotenuse, so cos(27) = .891 so .891=34/hypotenuse so x=34/.891 which is 38.16. Again, fair warning that I'm a tad rusty and may be making an error.

Answer 2

Well thank you anyways:)