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Mathematics 20 Online
OpenStudy (anonymous):

What is the value of n such that the expression x² + 11x + n is a perfect square trinomial? 11 25 30.25 36

OpenStudy (anonymous):

in a perfect square trinomial a^2 + b + c = 0, c = (.5b)^2, so it would be 5.5^2 or 30.25

OpenStudy (anonymous):

oh my* ax^2 + bx + c = 0 my bad

OpenStudy (anonymous):

A perfect square trinomial follows the form a^2 + 2ab + b^2, since a is 1 b is 1/2 of 11 which is 5.5 so b^2 is 30.25 as mridrik just answered.

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