Question

how would i find the y-intercept of this equation by hand?
p(x)= -(x-3)^2(1-x)^11(2+x)^5

Answer 1

p(x)= -(x-3)^2 (1-x)^11 (2+x)^5
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Let x = 0 and solve for y. all points on the y-axis has x-coordinate zero.

y = - (0 - 3)^2 (1-0)^11 (2+0)^5

Crank this out and see what you get. Then, I'll compare with what I got.

Answer 2

-9(1)(32)=-288
(0,-288) ?

Answer 3

I got a - 288.

y = - (0 - 3)^2 (1-0)^11 (2+0)^5
y =- (-3)^2 * 1 * 2^5
y =-( 9) * 1* 32
y = -288 --> ordered pair (0, -288)