y^2 + 36x +8y - 92 = 0 help! what are the vertices, intercept, foci, eccentricity and directrices. Help please

Question

campbell_st · Answer

so its in the form (y - k)^2 = 4a(x-h)

so y^2 +8y = 36x +92

complete the square for y

(y + 4)^2 = 36x + 92 + 16

(y + 4)^2 = 36(x + 3)

so the vertex is at (-3, -4)   a = 9  the directrix is x = -12  the parabola is concave right

focus is (6, -4)

anonymous · Answer

how do i get the intercepts?

moongazer · Answer

There is NO eccentricity and intercepts for parabola.
Eccentricity and intercepts are just for Ellipse and Hyperbola.

moongazer · Answer

y^2 + 36x +8y - 92 = 0 is the gen. equation of parabola

anonymous · Answer

why is that x = -12?? could you help me.

moongazer · Answer

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