Question

y^2+36x+8y-92 = 0 what are the intercepts of this equation in parabola?

Answer 1

put x=0 , y^2+8y-92 = 0 , y= 6.39 or y = -14.39 <-y-int
put y=0, 36x-92 = 0 , x=2.556 <- x-int

Answer 2

parabola has no intercepts. :)

Answer 3

im looking for the interceptS, so ill just made it positive negative? and transform it into the standard eq.

Answer 4

wow.didnt knew that. hehe thanks for the info

Answer 5

intercepts are just for ellipse and hyperbola.

Answer 6

i thought you're asking the x/y axes int, sorry :(

Answer 7

its ok. thanks by the way :))