Question

find the value of y' at x = pi/8 if y = 3tan2x+tan^3 2x.

a.22

b.24

c.26

d.28

Answer 1

y = 3tan2x+tan^3 2x
\[y'=6(\sec^2(2x)+\tan^2(2x)\sec^2(2x))\]
sub x=pi/8 into y'
y'=24