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simplify f(x)= (4x^2+7x-2) / 4x-1. using complete sentences explain why f(1)=3, f(0)=2 and f(-1), yet f(1/4) is undefined. show work please:(
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\[f(\frac{1}{4})\] is undefined becase \[4(\frac{1}{4})-1=1-1=0\] so the denominator will be zero, and you cannot divide by 0
\[f(1)=3\] because if you replace x by 1 you will get 3
and in fact \[f(x)=\frac{4x^2+7x-2}{ 4x-1}=\frac{(x+2)(4x-1)}{4x-1}=x+2\] so this function basically says "add 2" but it is still undefined at x = 1/4 because the equality i wrote above is only true if \[x\neq \frac{1}{4}\]
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