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Coordinates of two points are A (-2,6) and B (9.3). Find the coordinates of a point C on the x axis such that AC = BC.
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call that point (x,0) second coordinate is 0 becaues you are on the x axis
then you know that \[(x+2)^2+6^2=(x-9)^2+3^2\] by the distance formula. now you have a quadratic equation to solve
ty :)
actually i lied, you do not have a quadratic equation to solve, because when you expand the x^2 term will drop out
\[x^2+4 x+40 = x^2-18 x+90\] then \[4x+40=-18x+90\] etc
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Oh haha ok then. Thanks again though
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