Question

if y = 3tan2x + tan^32x,then dy/dx is equal to:
a.3sec^4 2x
b.6 sec^4 2x
c.-3sec^4 2x
d.-6sec^4 2x

Answer 1

\[y'=3(2x)' \sec^2(2x)+(2x)' \cdot 3\tan^{3-1}(2x) \sec^2(2x)\]

Answer 2

\[y'=6\sec^2(2x)+6 \tan^2(2x)\sec^2(2x)\]

Answer 3

little be of factoring and an idenitity will get you your answer

Answer 4

6tan^2(2x) = 6sec^4 2x? is this ryt?