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Mathematics 13 Online
OpenStudy (anonymous):

Factorise ax+by+ay+bx

OpenStudy (anonymous):

you can write \[a(x+y)+b(x+y)\] as a first step

OpenStudy (hoblos):

=a(x+y) + b(x+y) = (x+y)(a+b)

OpenStudy (anonymous):

then see that you have a common factor of \[x+y\] giving \[(a+b)(x+y)\]

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