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The sum of two numbers is 51. Their difference is 13. What is the smaller of the two numbers ? A . 18 B. 19 C. 20 D. 21 ?
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x+y=51 x-y=13 find y
\[x+y=51\] \[x-y=13\] add to get \[2x=64\] \[x=32\]
yeah x=32 then y=32-13=19
x+y=51 x-y=13 =>2y=51-13 =>y=38/2 =>y=19
TL:DR B is the answer
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