Question

Please factor the following polynomial completely
208p^2-325q^2

Answer 1

helps to know that both numbers have a common factor of 13

Answer 2

so start with
\[13(16p^2-25q^2)\] and once again factor as the difference of two square
\[a^2-b^2=(a+b)(a-b)\] this time with
\[a=6p, b=5q\]

Answer 3

sorry
\[a=4p, b=5q\]

Answer 4

hmm, continue :
\[13(16^{2}-25q ^{2}) =13(4p-5q)(4p+5q)\]