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Solve the system equations . 3x - 4y = -10 and 5x + 8y = -2 . A. (1,2) B. (2,1) C. (1,-2) D. (-2,1) ?
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3x-4y=-10 5x+8y=-2 Multiply first equation by 2 6x-8y=-20 5x+8y=-2 Now add these equations! 11x+0=-22 11x=-22 .... Will you show me how to solve the rest of this?
Just a moment
x = -2
Yep Yep! :)
\[3(-2)-4y=-10\] I just replaced x with -2 in one of the equations do you think you can solve for y
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y = -4 ?
-6-4y=-10 +6 +6 -4y=-4 y=1
nice try though alexis! :)
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