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1. 3(2x – 1) = 15 2. 6(x + 1) = 12 3. 2(4x + 3) = 22 solve for x
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3(2x – 1) = 15 (2x – 1) = 5 2x=6 x=3
6(x + 1) = 12 x+1 = 2 x=1
Although Callisto's method is correct, I'd suggest practising using the distributive property, as it seems to be what the question is looking for.
2(4x + 3) = 22 4x+3 = 11 4x =8 x=2
Thanks guys
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1. 3 (2 x - 1) = 15 2. 6 (x + 1) = 12 3. 2 (4 x + 3) = 22
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