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A board game has a spinner with ten equal sections, numbered 1 through ten . In order to win the game, Mae needs to spin at least a 6 on each of her last two turns. What's the probability of this happening? Answer one percent ten percent twenty-five percent thirty-six percent
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25%
thank u
how did u get that
okay... well think about it this way.. the differ sections are: 1,2,3,4,5,6,7,8,9, and 10 now... 5 of those are great than or equal to 6: 6,7,8,9,10 so if there are ten sections and 5 of them work.. that 1/2 or 50% but she needs to get that twice... so you take 1/2 and multiply it by 1/2 which is 1/4 or 25%
thank u so much
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no prob :)
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