Enter the equation of the line meeting the given conditions. Please put the equation instandard form. Containing C(3, 3) and D(-3, 2)
y= 1/6x + 5/2
or can also rewrite as 6y-x-15=0
Hi Radar, Great explation except that after cross multiplication you should end up with 6y=x+15 not (6y = x+18) you forgot to subtract the 3.
I was trying to figure why we weren't on track.
I see it now. I wish I could just go in there to correct it, I want the steps to be there. lol I am gonna try something
yea, :)
calculate slope: m=(3-2)/(3+3)=1/6 1/6=(y-3)/(x-3) cross multiply getting x-3=6y-18 6y=x+18-3 6y=x+15 y=1/6x+15/6 y=1/6x +5/2 this form is in the slope intercept form standard form: y-1/6x-5/2=0
I think I had better call it quits for tonight lol.
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