Question

Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. x2 + x +10 = 0
A. {3.2}
B. {-5.5, -2}
C. {-3.2, 3.2}
D. no real number solution

Answer 1

\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 2

But actually, just do b^2 - 4ac to make sure that it is even necessary to do quad form

Answer 3

(1)^2 - 4(1)(10) = 1 - 40 = -39

Since discriminant is negative, this means that there are no real solutions