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Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. x2 + x +10 = 0 A. {3.2} B. {-5.5, -2} C. {-3.2, 3.2} D. no real number solution
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\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
But actually, just do b^2 - 4ac to make sure that it is even necessary to do quad form
(1)^2 - 4(1)(10) = 1 - 40 = -39 Since discriminant is negative, this means that there are no real solutions
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