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f(x)=x^5-2x+1......find the equation of the tangent line at x=1
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Is it 0?
take the derivative, evaluate at 1 to find the slope, then use the point slope formula
\[f(1)=0\] \[f'(x)=5x^4-2\] \[f'(1)=3\] use \[y-y_1=m(x-x_1)\] with \[x_1=1,y_1=0, m=3\]
So i basically only did half of the equation?
yeaaa but you still did a good job
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lol thnks, but i still feel like a fail...i wnt to finish the WHOLE equation. ;(
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