Question

find points on y=2x^3+3x^2-12x+1 where tangent is horizontal. how do i solve this?

Answer 1

Take the derivative, set it to zero. That will give you the points where the tangent line is horizontal.

Answer 2

so the points would be my zeros ?

Answer 3

\[dy/dx =6x^2+6x-12\]
set this to zero beacuse tan 0 is when the gradient of the graph is zero
\[6x^2+6x-12=0\]
the answers would be 1,-2

Answer 4

ok got it ,thanks!

Answer 5

:)