the speed of the A&M freight train is 14 mph less than the speed of the A&M passanger train.the passanger train travels 400mi in the same time that thw freight train travels 330mi Find the speed of each train. thanks

Question

anonymous · Answer

system of linear equation application. . .

hero · Answer

d = rt
freight train: 330 = (r-14)t
passenger train 400 = rt

330 = rt - 14t
400 = rt

330 = 400 - 14t

14t = 400 - 330
14t = 70
t = 5
r = 80

hero · Answer

r - 14 = 80 - 14 = 66

Freight = 66
Passenger = 80

anonymous · Answer

wow, thanks Hero ;)

hero · Answer

That's the smoothest solution you'll ever see