An object is moving with constant speed in a straight line relative to the origin. The objects initial and final position vectors are respectively: u = i + 2j + 3k
v = 2i + j -4k

Find an expression for q, the position vector of the object when it has travelled a distance of x.

Question

An object is moving with constant speed in a straight line relative to the origin. The objects initial and final position vectors are respectively: u = i + 2j + 3k
v = 2i + j -4k

Find an expression for q, the position vector of the object when it has travelled a distance of x.

nottim · Answer

I'm doin the same stuff; I can't remember how to do this specifically; try your txtbook examples. sorry i didnt help much; studying for chem, bio and vectors test while doing eng assignment

anonymous · Answer

Do you think this may be right, (v-u) + xu

nottim · Answer

honestly couldnt tell you. it looks familiar, but im not sure

anonymous · Answer

Ok Thanks anyway

anonymous · Answer

help plz

anonymous · Answer

i hope it is q=u +(x/sqrt(51) (v-u)    (sqrt(51) for converting the drs of uv to dcs)

anonymous · Answer

whats drs?

anonymous · Answer

drs are direction ratios and dcs direction cosines

anonymous · Answer

Thanks, I just understood it now.