Question

find the critical points of y=x^2(x-2)^2

Answer 1

may want to start with
\[y=x^4-4 x^3+4 x^2\]

Answer 2

so
\[y'=4x^3-12x^2+8x= 4x(x^2-3x+2)\]\]

Answer 3

then set
\[4x(x^2-3x+2)=0\]
\[4x(x-2)(x-1)=0\] etc

Answer 4

thanx satellite73 :-)

Answer 5

yw