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<AOB = 5 degree <COD = 15 degree
How do you solve for x? That is the part I could not figure out. Thank you.
let <COD = x degree then <AOB =x/3 since for a straight line sum of all angles about a point on it is 180 degree so <COD + <AOB = 180 - 160 means x + x/3 = 20 4x/3 = 20 4x = 20*3 x = 60/4 x = 15 so <COD = 15 <AOB = 15/3 = 5
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