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OpenStudy (anonymous):
Find the indefinite integral of cos(x^1/2) dx ATTEMPT: I let u = x^1/2 Then, du = 1/2(x^-1/2)dx <-- but that term is not in the integrand..
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OpenStudy (anonymous):
Nevermind, I remember.
OpenStudy (phi):
in case someone is wondering: \[ du= \frac{1}{2\sqrt{x} }dx \] \[ dx= 2 u du \] and the integral is \[\int\limits u \cos(u) du\] which tackled using integration by parts
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