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Mathematics 16 Online
OpenStudy (anonymous):

okay who can help me?

OpenStudy (anonymous):

Me but it depends with what

OpenStudy (anonymous):

f(x) = cos x − sin x, [0, 2π] use MVT to find a point that satisfies c.

OpenStudy (precal):

\[\frac{f(b)-f(a)}{b-a}=f \prime (c)\] do f(b) and f(a) first a=0 b=2pi

OpenStudy (precal):

@dleather25 waiting for you response

OpenStudy (anonymous):

yes! they do

OpenStudy (precal):

no I believe I asked you to calculate f(b) and f(a)

OpenStudy (precal):

ok well I tried to help you..... good luck

OpenStudy (anonymous):

2pi -0 - 0 - 2pi/ 2pi - 0

OpenStudy (precal):

do them separate please what is f(b) equal to? what is f(a) equal to?

OpenStudy (anonymous):

f(b) = cos x i guess and sinx = f(a)/

OpenStudy (precal):

f(b)=f(2pi) f(a)=f(0)

OpenStudy (anonymous):

okay, so now the derivative of sinx - cos x = something..

OpenStudy (precal):

no you still did not tell me what they are equal to? state each one please

OpenStudy (anonymous):

sin 2pi = .109

OpenStudy (anonymous):

cos 2pi = .99399

OpenStudy (anonymous):

cos (0) = 1

OpenStudy (anonymous):

sin 0 = 0

OpenStudy (anonymous):

1- .109 = .891

OpenStudy (anonymous):

.891/2pi

OpenStudy (anonymous):

is that good?

OpenStudy (precal):

no do you not know the exact values of sin(0), cos(0), sin(2pi), cos(2pi)? I hope you are not taking the AP exam for calculus

OpenStudy (anonymous):

??? What? Do you know the answer, I've been in a library for 3 and a half hours doing my calculus homework, and have no clue how to do this problem, f(b) - f(a) / b-a = f ' (c)

OpenStudy (precal):

f(b)=f(2pi)=cosp(2pi)-sin(2pi)=? f(a)=f(0)=cos(0)-sin(0)=?

OpenStudy (precal):

yes, I know a bit about MVT

OpenStudy (anonymous):

.88455

OpenStudy (precal):

You still need to answer the above part so we can move on. no, go to the website I posted and look up these exact values? AP calculus will not accept that, neither will any college professor

OpenStudy (anonymous):

ok cos 2pi = .9939931166 and sin 2pi = .1094426069 so .9939931166-.1094426069 = .8845505097 / cos(0) aka (1)

OpenStudy (precal):

did you go to the website? There are no decimals - those values are approximations we want exact solutions, did your precal teacher not show you how to derive those values using the unit circle????

OpenStudy (anonymous):

no? just use decimals? what does it matter..

OpenStudy (precal):

it matters !!! please go to the website and look at those values.

OpenStudy (anonymous):

ok and sin 0 = 0 and cos 0 = 1...

OpenStudy (precal):

now calculate f(b) and f(a)

OpenStudy (precal):

ok good bye!!!

OpenStudy (anonymous):

what are you talking about i did!!!!!

OpenStudy (anonymous):

why dont you calculate it? obviously i dont know what the heck you're talking about so you do it and tell me how you did it/

OpenStudy (precal):

no f(b) = look above when I stated it and had a ? no f(a)= same comment

OpenStudy (anonymous):

so sin 2pi = ???

OpenStudy (precal):

go back to that website

OpenStudy (anonymous):

sin 2 pi = 0

OpenStudy (precal):

f(b)=f(2pi)=cosp(2pi)-sin(2pi)=? f(a)=f(0)=cos(0)-sin(0)=?

OpenStudy (precal):

waiting ............. f(b)=f(2pi)=cosp(2pi)-sin(2pi)=? f(a)=f(0)=cos(0)-sin(0)=?

OpenStudy (anonymous):

.99 - 0 = .9939 blahhh...

OpenStudy (precal):

did we go back to decimal? decimals are bad, begone decimals.

OpenStudy (anonymous):

cos 2pi = 2pi??

OpenStudy (precal):

really???? Maybe you should attend tutoring with your teacher or ask one of your friends. I really must go........ :(

OpenStudy (anonymous):

what is the answer

OpenStudy (precal):

sorry, I am not interested in giving the solution. I am only interested in the process and helping you learn. Last post, I will not respond anymore

OpenStudy (precal):

Read the rules of behavior...... I have reported you for abuse

OpenStudy (anonymous):

I dont even care man, how you gonna just leave like that, i dont come here just to waste my time

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