okay who can help me?
Me but it depends with what
f(x) = cos x − sin x, [0, 2π] use MVT to find a point that satisfies c.
\[\frac{f(b)-f(a)}{b-a}=f \prime (c)\] do f(b) and f(a) first a=0 b=2pi
@dleather25 waiting for you response
yes! they do
no I believe I asked you to calculate f(b) and f(a)
ok well I tried to help you..... good luck
2pi -0 - 0 - 2pi/ 2pi - 0
do them separate please what is f(b) equal to? what is f(a) equal to?
f(b) = cos x i guess and sinx = f(a)/
f(b)=f(2pi) f(a)=f(0)
okay, so now the derivative of sinx - cos x = something..
no you still did not tell me what they are equal to? state each one please
sin 2pi = .109
cos 2pi = .99399
cos (0) = 1
sin 0 = 0
1- .109 = .891
.891/2pi
is that good?
no do you not know the exact values of sin(0), cos(0), sin(2pi), cos(2pi)? I hope you are not taking the AP exam for calculus
??? What? Do you know the answer, I've been in a library for 3 and a half hours doing my calculus homework, and have no clue how to do this problem, f(b) - f(a) / b-a = f ' (c)
f(b)=f(2pi)=cosp(2pi)-sin(2pi)=? f(a)=f(0)=cos(0)-sin(0)=?
yes, I know a bit about MVT
.88455
You still need to answer the above part so we can move on. no, go to the website I posted and look up these exact values? AP calculus will not accept that, neither will any college professor
ok cos 2pi = .9939931166 and sin 2pi = .1094426069 so .9939931166-.1094426069 = .8845505097 / cos(0) aka (1)
did you go to the website? There are no decimals - those values are approximations we want exact solutions, did your precal teacher not show you how to derive those values using the unit circle????
no? just use decimals? what does it matter..
it matters !!! please go to the website and look at those values.
ok and sin 0 = 0 and cos 0 = 1...
now calculate f(b) and f(a)
ok good bye!!!
what are you talking about i did!!!!!
why dont you calculate it? obviously i dont know what the heck you're talking about so you do it and tell me how you did it/
no f(b) = look above when I stated it and had a ? no f(a)= same comment
so sin 2pi = ???
go back to that website
sin 2 pi = 0
f(b)=f(2pi)=cosp(2pi)-sin(2pi)=? f(a)=f(0)=cos(0)-sin(0)=?
waiting ............. f(b)=f(2pi)=cosp(2pi)-sin(2pi)=? f(a)=f(0)=cos(0)-sin(0)=?
.99 - 0 = .9939 blahhh...
did we go back to decimal? decimals are bad, begone decimals.
cos 2pi = 2pi??
really???? Maybe you should attend tutoring with your teacher or ask one of your friends. I really must go........ :(
what is the answer
sorry, I am not interested in giving the solution. I am only interested in the process and helping you learn. Last post, I will not respond anymore
Read the rules of behavior...... I have reported you for abuse
I dont even care man, how you gonna just leave like that, i dont come here just to waste my time
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