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NEED HELPPP!!! A rectangle has a length of x. Its width is 3 feet longer than twice the length. Find the dimensions if its area is 80 ft2. Round to the nearest tenth of a foot
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w=2x+3 wx=80 use substitution to solve the variables
i did...but it isn't working
plug "2x+3" in for w in the second eqn.
(2x+3)x=80
how is x 16?..that doesn't equal to 80 when you plug 16 into x
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srry tht not what i meant to type ...
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