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Simplify: √(a^2 +2a +1)
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\[\sqrt{(a+1)^2}\]
then that would just be a+1 ?
Yes
Do you know how he got (a + 1) out of the initial equation though?
yes... a^2 +2a +1 when factored is (a+1)^2
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Alright, just making sure :)
thanks :)
\[\sqrt{a^2+2a+1}=\sqrt{(a+1)^2}=|a+1|\]
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