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Mathematics 13 Online
OpenStudy (anonymous):

dddddirec

OpenStudy (anonymous):

OpenStudy (dumbcow):

Let x be horizontal distance, h be vertical distance \[\tan 65 = \frac{h}{x}\] \[\tan 40 = \frac{h}{x+290}\] solve each for h, then set them equal to each other \[x \tan 65 = (x+290) \tan 40\] \[x = \frac{290 \tan 40}{\tan 65 - \tan 40}\]

OpenStudy (anonymous):

113?

OpenStudy (dumbcow):

oh and angle A is 50-25 = 25

OpenStudy (dumbcow):

i get x= 186.41 h = 399.75

OpenStudy (anonymous):

How is x 186.41? I get 112.63

OpenStudy (dumbcow):

tan40 = .84 tan 65 = 2.14 --> (290*.84)/(2.14-.84) = 186.41

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