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OpenStudy (anonymous):
prove: if m1,m2>1 and a is congruent to b(mod m1m2), then a is congruent to b (mod m1)
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OpenStudy (anonymous):
given that a-km1m2=b for some integer k now it can be re written as a-k'm1 =b for some integer k'=km2 and hence proved
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