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The product of two consecutive integers is three less than three times their sum.Find the integers.
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are the numbers 6 and 5
n(n+1) = 3(2n+1) -3
Let x and x + 1 be the consecutive integers x(x+1) = 3(x + x + 1) – 3 x^2 + x = 3(2x + 1) – 3 x = 0 and x = 5 ?
n^2 -5n = 0
then we factor right
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right pull out an n
n(n-5)=0
n=0
n=5
yup ;D
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So, the pairs are 0,1 and 5,6
how is it 0 and 1?
I understand how it 0 where did the 1 come from
Nvm now I know why its 0 and 1 because it consecutive integers going by one silly me
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