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1/1-3+1/1+3=10/x^2-9
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do you mean (1/1-3) +(1/1+3) =10/(x^2-9) ?
yes
could you help me solve ?
(1/1-3) +(1/1+3) =10/(x^2-9) (-1/2) + 1/4 =10/(x^2-9) -1/4 = 10/(x^2-9) 9-x^2 = 40 x^2 = -31 ...... \[x=\pm\sqrt{31} i\]
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