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When simplifying the expression the fraction 2 over x plus the fraction 2 over x minus 1 plus the fraction 2 over x plus 2. The denominator is x(x+1)(x–1), what is the numerator?
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First i have to say that this is too much grammar
We will take this one step at a time
2 over x => 2/x 2 over x minus 1 => 2/(x-1) 2 over x plus 2 => 2/(x+2) Now our expression will be, 2/x + 2/(x-1) + 2/(x+2) The denominator will be => x(x-1)(x+2) The numerator will be => 2(x-1)(x+2) + 2(x)(x+2) + 2(x)(x-1)
soo 4x^2+8x+2?
or 6x^2+8x+4
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