Question

How do you solve 3x-10=x+30 ?

Answer 1

subtract x from both side
2x -10 = 30
add 10 for both sides
2x = 40
divide both sides by 2
x = 20

Answer 2

thankyou, this really helped, do you use this method to solve all equations?

Answer 3

We have
\[3x-10=x+30\]
Subtract x from both sides
\[3x-10-x=x+30-x\]
\[3x-10- x=\cancel x+30-\cancel x\]
\[2x-10=30\]
Add 10 to both sides
\[2x-10+10=30+10\]
\[2x-\cancel{10}+\cancel {10}=30+10\]
We get
\[2x=40\]
divide both sides by 2
\[\frac{2x}{2}=\frac{40}{2}\]
\[x=20\]



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