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Find the Basis for the Rank(A transpose)?
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A=[3,4;6,8]
First step is to find \(A^T\) This is \[A^T=\left[\begin{matrix} 3&6\\4&8 \end{matrix} \right]\]So now you just need to find a basis for that.
However, you should notice that column 2 is just column 1 times 2.
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