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the corresponding sides of two similar rectangles are 14 and 8 the area of the smaller rectanlge is 57 square
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find the area of the larger rectangle
ratio of sides is 14 to 8 or 7 to 4 ratio of the areas will be 49 to 16
\[\frac{49}{16}=\frac{x}{57}\] \[x=\frac{57\times 49}{16}\]
the area of the larger one has top be more than 57 because that is the area of the smaller rectangle
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The corresponding sides of two trapezoids is 24 and 30 the area of the larger trapezoid is 61 what is the area of the smaller trapezoid
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