At 9:00 pm saturday morning, two bicyclist heading in opposite directions pass each other on a bicyclist path. The bicyclist heading north is riding 5 km/jpir faster than the bicyclist heading south. At 10:45, they are 47.25 km apart. Find the two bicyclists rates

Question

anonymous · Answer

Time traveled is 7/4 hours.  Let v be the speed of the slower rider, so$$7/4(2v+5)=47.25=189/4$$

anonymous · Answer

I think you should be able to take it from there.

anonymous · Answer

@Luis Rivera: I think your times are off; 45 minutes is 3/4 of an hour, not 2/3.

anonymous · Answer

I think the bicyclists are going 16 and 11 kph, north and south respectively.