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if f(x)=x/x^2-16, what is the value of f(-10)
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f(x)=x/x^2-16 f(-10)=-10/(-10)^2-16 =-10/100-16 =-1/10-16 =(-1-16*10)/10 =-161/10 =-16.1
u didn't mean f(x)=x/(x^2-16) did u
yes,i meant the second way
ok f(x)=x/(x^2-16) f(-10)=-10((-10)^2-16)=-10(100-16)=-10/84=-5/42=-0.11
ok, thanks!
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