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Physics 13 Online
OpenStudy (anonymous):

A fish swimming in a horizontal plane has velocity varrowboldi = (4.00 ihatbold + 1.00 jhatbold) m/s at a point in the ocean where the position relative to a certain rock is rarrowboldi = (16.0 ihatbold − 1.60 jhatbold) m. After the fish swims with constant acceleration for 15.0 s, its velocity is varrowbold = (25.0 ihatbold − 1.00 jhatbold) m/s. (a) What are the components of the acceleration of the fish?

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