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Find a if the 17th and 18th terms of the expansion of (2+a)^50 are equal
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if i am no mistaken the 17 term is \[\dbinom{50}{16}2^{16}a^{34}\]
and similarly 18 term is \[\dbinom{50}{17}2^{17}a^{33}\] so i guess we can set them equal and solve
\[\dbinom{50}{16}2^{16}a^{34}=\dbinom{50}{17}2^{17}a^{33}\] \[\dbinom{50}{16}a=\dbinom{50}{17}2\]
and so \[a=\frac{2\dbinom{50}{17}}{\dbinom{50}{16}}\] whatever that is
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