Question

The langth of a rectangle is twice the width. The area is 450yd^2. find the langhth and width.

Answer 1

let the width by x yd,
let the length be 2x yd,

Area = w x l
= (x)(2x)
450 = 2x^2
225 = x^2
x^2 - 225 = 0
(x-15)(x+15) = 0
therefore, x = -15 (N.A., rejected) , x =15

thus x = 15

Length = 30 yd
Width = 15 yd.....

Answer 2

thank you